WebFind the vector equation of the plane passing through the origin and containing the line r i j k i j k r ¯ = ( i ^ + 4 j ^ + k ^) + λ ( i ^ + 2 j ^ + k ^). Advertisement Remove all ads Solution The vector equation of the plane passing through A A ( a ¯) and perpendicular to the vector n n ¯ is r n a n r ¯. n ¯ = a ¯. n ¯ ... (1) WebNov 12, 2009 · Fashion Week & Fashion Show Fashion Week & Fashion Show FASHION SHOW Nataliya Gotsiy modeling for Cynth[ia Rowley, Spring 2007 New York Fashion Week Models wearing Slava Zaitsev fashions in Moscow, January 2007. Men's fashions for 1948, shown in Los Angeles A fashion show is an event put on by a fashion …
Finding a vector which lies in the plane perpendicular to a line, and ...
WebHence, the given lines are coplanar. The plane determined by these lines is given by. ∴ `bar"r".(bar"b"_1 xx bar"b"_2) = bar"a"_1.(bar"b"_1 xx bar"b"_2)` i.e. `bar"r".(-hat"i" + 2hat"j" - … WebThe plane determined by these lines is given by ∴ r b b a b b r ¯. ( b ¯ 1 × b ¯ 2) = a ¯ 1. ( b ¯ 1 × b ¯ 2) i.e. r i j k r ¯. ( - i ^ + 2 j ^ - k ^) = 7 Hence, the given lines are coplnar and the equation of the plane determined bt these lines is r i j k r ¯. ( - i ^ + 2 j ^ - … to his scribe adam
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WebShow that the lines and r → = 3 i ^ + 2 j ^ − 4 k ^ + λ ( i ^ + 2 j ^ + 2 k ^) and r → = 5 i ^ − 2 j ^ + μ ( 3 i ^ + 2 j ^ + 6 k ^) are intersecting. Hence, find their point of intersection. … WebShow that lines: → r = ^ i + ^ j + ^ k + λ (^ i − ^ j + ^ k) → r = 4 ^ j + 2 ^ k + μ (^ 2 i − ^ j + ^ 3 k) are coplanar. Also, find the equation of the plane containing these lines. WebMar 17, 2024 · Best answer Given lines are →r = 3^i + 2^j − 4^k + λ(^i + 2^j + 2^k) r → = 3 i ^ + 2 j ^ − 4 k ^ + λ ( i ^ + 2 j ^ + 2 k ^) and →r = 5^i − 2^j + μ(3^i + 2^j + 6^k) r → = 5 i ^ − 2 j ^ + μ … to his mistress